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Tuesday, April 23, 2013

Physics

Physics Conservation of Momentum 1. Trial 1 T1 (s) T2 (s) Vi (m/s) V2 (m/s) 0 0.071 0.351 1 0.111 0.225 2 0.118 0.215 Trial 2 0 0.061 .409 1 0.092 0.272 2 0.101 0.248 Trial 3 0 0.057 0.440 1 0.083 0.
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300 2 0.088 0.283 atomic pile of car 1 = 993.0 g Mass of car 2 = 496.7 g 2. trial 1 auto 1 nerve impulse before meeting P=mv P=(.993kg)(.351m/s) P= .349 kgm/s Car 2 neural impulse before collision P=mv P=(.4967kg)(0m/s) P = 0 kgm/s Objects (or both cars together) pulsation after collision P=mv P=(1.4897kg)(.225) P = .335 kgm/s Trial 2 Car 1 momentum before collision P=mv P= (.993kg)(.409m/s) P= .406 kgm/s Car 2 momentum before collision P=mv P= (.4967kg)(0) P= 0 kgm/s Objects momentum after collision P=mv P = (1.4897kg)(.272m/s) P= .405 kgm/s ...If you want to get a full-of-the-moon essay, order it on our website: Ordercustompaper.com

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